Fix invalid code link, update exception message
Update RuntimeException message to use the correct method name (sendMessageAtFrontOfQueue() instead of sendMessageAtTime()). Fix code reference in comment. Test: m Change-Id: I0c736c8871d8af4778a688d5c77a413e72b81880
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@@ -182,7 +182,7 @@ public class Handler {
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*
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* Asynchronous messages represent interrupts or events that do not require global ordering
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* with respect to synchronous messages. Asynchronous messages are not subject to
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* the synchronization barriers introduced by {@link MessageQueue#enqueueSyncBarrier(long)}.
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* the synchronization barriers introduced by {@link MessageQueue#postSyncBarrier()}.
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*
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* @param async If true, the handler calls {@link Message#setAsynchronous(boolean)} for
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* each {@link Message} that is sent to it or {@link Runnable} that is posted to it.
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@@ -203,7 +203,7 @@ public class Handler {
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*
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* Asynchronous messages represent interrupts or events that do not require global ordering
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* with respect to synchronous messages. Asynchronous messages are not subject to
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* the synchronization barriers introduced by {@link MessageQueue#enqueueSyncBarrier(long)}.
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* the synchronization barriers introduced by {@link MessageQueue#postSyncBarrier()}.
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*
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* @param callback The callback interface in which to handle messages, or null.
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* @param async If true, the handler calls {@link Message#setAsynchronous(boolean)} for
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@@ -743,7 +743,7 @@ public class Handler {
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MessageQueue queue = mQueue;
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if (queue == null) {
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RuntimeException e = new RuntimeException(
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this + " sendMessageAtTime() called with no mQueue");
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this + " sendMessageAtFrontOfQueue() called with no mQueue");
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Log.w("Looper", e.getMessage(), e);
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return false;
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}
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